(2^{2}) and (2)^{2}

Hello,

the difference beetween (\(2^2\)) and (\(2^2\)) is 0 because (\(2^2-2^2\)) is 0.

(If you subtract and the minuend and subtrahend are the same,

the result is ALWAYS 0.)

Straight

Since (2)^{2}=4 and (2^{2})=4, subtracting them gives 0. Meaning no difference.